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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: *Tìm x ∈ Q, biết: a) ($2x-3)^{2}$ = 16 b) ($3x-2)^{5}$ = -243

Toán Lớp 7: *Tìm x ∈ Q, biết:
a) ($2x-3)^{2}$ = 16
b) ($3x-2)^{5}$ = -243

Comments ( 2 )

  1. @Thỏ
    a) $(2x – 3)^{2}$ = 16
    ⇒ $(2x – 3)^{2}$ = $4^{2}$ 
    ⇒ \(\left[ \begin{array}{1}2x – 3 = 4\\2x – 3 = -4\end{array} \right.\)
    ⇒ \(\left[ \begin{array}{l}2x = 7\\2x = -1\end{array} \right.\)
    ⇒ \(\left[ \begin{array}{l}x=\frac{7}{2} \\x= \frac{-1}{2} \end{array} \right.\)
    b) $(3x – 2)^{5}$ = -243
    ⇒ $(3x – 2)^{5}$ = $-3^{5}$ 
    ⇒ $3x – 2^{}$ = -3
    ⇒ $3x^{}$ = -1
    ⇒ x = -1/3
     

  2. Đáp án:
     
    Giải thích các bước giải:
     

    toan-lop-7-tim-q-biet-a-2-3-2-16-b-3-2-5-243

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222-9+11+12:2*14+14 = ? ( )