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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm x c, 172.x^2 – 7^9:98^3=1/8 d, 3^x+2+3^x=810

Toán Lớp 6: Tìm x
c, 172.x^2 – 7^9:98^3=1/8
d, 3^x+2+3^x=810

Comments ( 2 )

  1. Lời giải và giải thích chi tiết:
    $c)$ $172$ × $x^{2}$ – $7^{9}$ ÷ $98^{3}$ = $\frac{1}{8}$
    $172$ × $x^{2}$ – $42,875$ = $0,125$
    $172$ × $x^{2}$ = $0,125$ + $42,875$ = $43$
    $x^{2}$ = $43 ÷ 172$ = $0,25$
    $x^{2}$ = ( ±$0,5$ )²
    ⇒ $x$ = $0,5$
        $x$ = $-0,5$
    $Vậy$ $x$ ∈ { $0,5 ; -0,5$ }
    $d)$ $3^{x + 2}$ + $3^{x}$ = $810$
    ⇒ $3^{x}$ × $3^{2}$ + $3^{x}$ = $810$
    ⇒  $3^{x}$ × ( $3^{2}$ + $1$ ) = $810$
    ⇒ $3^{x}$ × $10$ = $810$
    ⇒ $3^{x}$ = $810$ ÷ $10$ = $81$
    ⇒ $3^{x}$ = $( ±3 )^{4}$ 
    $Vậy$ $x$ ∈ { $4, -4$ }
     

  2. Giải đáp:
    $\\$
    c,
    172 × x^2 – 7^9 ÷ 98^3 = 1/8
    ↔ 172 × x^2 – 40353607 ÷ 941192 = 1/8
    ↔ 172 × x^2 – 343/8 = 1/8
    ↔ 172 × x^2 = 1/8 + 343/8
    ↔ 172 × x^2 = 43
    ↔ x^2 = 43 ÷ 172
    ↔x^2=1/4
    ↔ \(\left[ \begin{array}{l}x^2=(\dfrac{1}{2})^2\\x^2=(\dfrac{-1}{2})^2\end{array} \right.\) 
    ↔ \(\left[ \begin{array}{l}x=\dfrac{1}{2}\\x=\dfrac{-1}{2}\end{array} \right.\) 
    Vậy x=1/2 hoặc x=(-1)/2
    $\\$
    d,
    3^{x+2} + 3^x =810
    ↔ 3^x × 3^2 + 3^x × 1 = 810
    ↔ 3^x × 9 + 3^x × 1 = 810
    ↔ 3^x × (9+1)=810
    ↔3^x × 10 = 810
    ↔ 3^x = 810 ÷10
    ↔ 3^x =81
    ↔ 3^x = 3^4
    ↔x=4
    Vậy x=4
     

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222-9+11+12:2*14+14 = ? ( )

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