Toán Lớp 6: tìm x a,6x-1=7 b, 25-(2+x)=65 c,2x+1=32 d,(x-25).(7+x)=0

Question

Toán Lớp 6:  tìm x a,6x-1=7 b, 25-(2+x)=65 c,2x+1=32 d,(x-25).(7+x)=0

giangnguyen33 · Answer

a, 6x - 1 = 7   &rArr; 6x = 8   &rArr; x = 8 : 6   &rArr; x = $ frac{4}{3}$    b, 25 - (2 + x) = 65   &rArr; 2 + x = 25 - 65   &rArr; 2 + x = -40   &rArr; x = -40 - 2   &rArr; x = -42   c, 2x + 1= 32   &rArr; 2x = 32 - 1   &rArr; 2x = 31   &rArr; x = 31 : 2   &rArr; x = $ frac{31}{2}$   d, (x - 25)(7 +x) = 0   &rArr;  ( left[  begin{array}{l}x-25=0  7+x=0 end{array}  right. )   &rArr;  ( left[  begin{array}{l}x=25  x=-7 end{array}  right. )

diemchau · Answer

$#RinnBoy$     $#anhsangsoiduong.vn$     Giải đáp +   Lời giải và giải thích chi tiết:     a,  6x - 1 = 7      =>  6x = 8      =>  x = 8 : 6      =>  x = $ frac{4}{3}$      b, 25 - (2 + x) = 65      =>  2 + x = 25 - 65      =>  2 + x = -40      =>  x = -40 - 2      =>  x = -42     c, 2x + 1= 32      =>  2x = 32 - 1      =>  2x = 31      =>  x = 31 : 2      =>  x = $ frac{31}{2}$     d, (x - 25)(7 +x) = 0      =>   ( left[  begin{array}{l}x-25=0  7+x=0 end{array}  right. )      =>   ( left[  begin{array}{l}x=25  x=-7 end{array}  right. )