Toán Lớp 8: b) (2????^3 − 5????^2 + 5???? − 3): (????^2 − ???? + 1)
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Toán Lớp 8: b) (2????^3 − 5????^2 + 5???? − 3): (????^2 − ???? + 1)
Comments ( 2 )
=(2x³-2x²-3x²+2x+3x-3):(x²-x+1)
=(2x³-2x²+2x-3x²+3x-3):(x²-x-1)
=2x(x²-x+1)-3(x²+x-1):(x²-x-1)
=(2x-3)(x²-x+1):(x²-x+1)
=2x-3
Vậy (2x³-5x²+5x-3):(x²-x+1)=2x-3
=> Áp dụng phương pháp: Tách hạng tử, nhóm hạng tử, đặt nhân tử chung để tính 2x^3 -5x^2 +5x-3