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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tìm MTC: `2/(9x^2 – 1)`; `(4x)/(1 – 3x)`

Tháng Ba 10, 2023 Toán học 2 Comments 0 views

Toán Lớp 8: tìm MTC: 2/(9x^2 – 1); (4x)/(1 – 3x)

Comments ( 2 )

  1. chauhoangmy98
    chauhoangmy98
    10 Tháng Ba, 2023 at 3:45 sáng
    Reply
    Ta có:
    $9x^2-1=(3x)^2-1=(3x-1)(3x+1)
    $⇒$ $MTC=(3x-1)(3x+1)$
    $\dfrac{2}{9x^2-1}=\dfrac{2}{(3x-1)(3x+1)}$ 
    $\dfrac{4x}{1-3x}=\dfrac{-4x}{3x-1}=\dfrac{-4x(3x+1)}{(3x-1)(3x+1)}$ 
     

  2. quynhthanhnhu
    quynhthanhnhu
    10 Tháng Ba, 2023 at 3:44 sáng
    Reply
    MTC:(1-3x)(3x+1)
    2/(9x^2-1)=-2/((3x)^2-1^2)=2/((1-3x)(3x+1))
    (4x)/(1-3x)=(4x(3x+1))/((1-3x)(3x+1))
     

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222-9+11+12:2*14+14 = ? ( )

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