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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x 1) 8x ³ -12x ² + 6x -1 ≡ 0 2)x ³ + 9x ² +27x +27 ≡ 0

Toán Lớp 8: Tìm x
1) 8x ³ -12x ² + 6x -1 ≡ 0
2)x ³ + 9x ² +27x +27 ≡ 0

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
    1)
    8x^3-12x^2+6x-1=0
    <=> (2x-1)^3=0
    <=> 2x-1=0
    <=> 2x=1
    <=> x=1/2
    Vậy x=1/2
    2)
    x^3+9x^2+27x+27=0
    <=> (x+3)^3=0
    <=> x+3 =0
    <=> x=-3
    Vậy x=-3

  2. $#Dứa$
    a, 8x³ – 12x² + 6x -1 = 0
    ⇔ (2x)³ – 31(2x)².1 + 3.2x.1² – 1³
    ⇔ (2x – 1)³
    ⇔ 2x – 1 = 0
    ⇔ 2x = 1
    ⇔ x = $\frac{1}{2}$ 
    b, x³ + 9x² + 27x + 27 = 0
    ⇔ x³ + 3.x².3 + 3.x.3² + 3³
    ⇔ (x + 3)³
    ⇔ x + 3 = 0
    ⇔ x = -3
     

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222-9+11+12:2*14+14 = ? ( )

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