Toán Lớp 8: phân tích thành nhân tử
a) x-1(x $\geq$ 0) x ²-3 x √x-27(x $\geq$ 0)
b) $x^{2}$ +2 √2x +2
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Toán Lớp 8: phân tích thành nhân tử
a) x-1(x $\geq$ 0) x ²-3 x √x-27(x $\geq$ 0)
b) $x^{2}$ +2 √2x +2
Comments ( 2 )
x^2-3=(x+\sqrt{3})(x-\sqrt{3})
x\sqrt{x}-27=\sqrt{x^3}-3^3=(sqrt{x}-3)(x+\sqrt{x}+9)
b)x^2+2\sqrt{2}x+2=x^2+2.\sqrt{2}.x+(\sqrt{2})^2=(x+\sqrt{2})^2