Giải đáp: x=5 Lời giải và giải thích chi tiết: \(\begin{array}{l}DK:x \ne \left\{ {1;3} \right\}\\\dfrac{2}{{x – 3}} + \dfrac{{x – 5}}{{x – 1}} = 1\\ \to \dfrac{{2\left( {x – 1} \right) + \left( {x – 3} \right)\left( {x – 5} \right) – \left( {x – 3} \right)\left( {x – 1} \right)}}{{\left( {x – 1} \right)\left( {x – 3} \right)}} = 0\\ \to 2x – 2 + {x^2} – 8x + 15 – {x^2} + 4x – 3 = 0\\ \to – 2x + 10 = 0\\ \to x = 5\end{array}\) Trả lời
DK:x \ne \left\{ {1;3} \right\}\\
\dfrac{2}{{x – 3}} + \dfrac{{x – 5}}{{x – 1}} = 1\\
\to \dfrac{{2\left( {x – 1} \right) + \left( {x – 3} \right)\left( {x – 5} \right) – \left( {x – 3} \right)\left( {x – 1} \right)}}{{\left( {x – 1} \right)\left( {x – 3} \right)}} = 0\\
\to 2x – 2 + {x^2} – 8x + 15 – {x^2} + 4x – 3 = 0\\
\to – 2x + 10 = 0\\
\to x = 5
\end{array}\)