Toán Lớp 8: 2/X-3+X-5/x-1=1
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Toán Lớp 8: 2/X-3+X-5/x-1=1
giải bất phương trình
Comments ( 2 )
DK:x \ne \left\{ {1;3} \right\}\\
\dfrac{2}{{x – 3}} + \dfrac{{x – 5}}{{x – 1}} = 1\\
\to \dfrac{{2\left( {x – 1} \right) + \left( {x – 3} \right)\left( {x – 5} \right) – \left( {x – 3} \right)\left( {x – 1} \right)}}{{\left( {x – 1} \right)\left( {x – 3} \right)}} = 0\\
\to 2x – 2 + {x^2} – 8x + 15 – {x^2} + 4x – 3 = 0\\
\to – 2x + 10 = 0\\
\to x = 5
\end{array}\)