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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm đa thức P ( x ) , biết : a , P (x ) + x – 4 = -5x^4 – 3x^3 + x – 1

Toán Lớp 7: Tìm đa thức P ( x ) , biết :
a , P (x ) + x – 4 = -5x^4 – 3x^3 + x – 1

Comments ( 2 )

  1. $P(x)+x-4=-5x^{4}-3x^{3}+x-1$
    $P(x)=-5x^{4}-3x^{3}+x-1-x+4$
    $P(x)=-5x^{4}-3x^{3}+3$
    Vậy $P(x)=-5x^{4}-3x^{3}+3$

  2. P(x) + x – 4 = -5x^4 – 3x^3 + x – 1
    P(x) +(x-4) = -5x^4 – 3x^3 + x – 1
    P(x) = (-5x^4 – 3x^3 + x – 1) – (x – 4)
    P(x) = -5x^4 – 3x^3 + x – 1 – x + 4
    P(x) = -5x^4 – 3x^3 + (x – x) + (-1 + 4)
    P(x) = -5x^4 – 3x^3 + 3
    VậyP(x) = -5x^4 – 3x^3 + 3

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222-9+11+12:2*14+14 = ? ( )