Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: `cho x/y = m/n . chứng minh 2x+3y / 2x-3y = 2m+3n / 2m-3n`

Toán Lớp 7: cho x/y = m/n . chứng minh 2x+3y / 2x-3y = 2m+3n / 2m-3n

Comments ( 2 )

  1. ~ Bạn tham khảo ~
    Đặt x/y=m/n=k
    => x=yk;m=nk
    Thay vào ta có :
    [2x+3y]/[2x-3y]=[2yk+3y]/[2yk-3y]=[y(2k+3)]/[y(2k-3)]=[2k+3]/[2k-3] (1)
    [2m+3n]/[2m-3n]=[2nk+3n]/[2nk-3n]=[n(2k+3)]/[n(2k-3)]=[2k+3]/[2k-3] (2)
    Từ (1),(2)=> [2x+3y]/[2x-3y]=[2m+3n]/[2m-3n] (Đpcm)

  2. Giải đáp:
    $\\$
    Đặt x/y = m/n = k
    \(\left\{ \begin{array}{l}\dfrac{x}{y}=k\\ \dfrac{m}{n}=k\end{array} \right.\)
    ↔ \(\left\{ \begin{array}{l}x=yk\\m=nk\end{array} \right.\)
    Có : (2x+ 3y)/(2x – 3y)
    = (2yk + 3y)/(2yk -3y)
    = (y (2k + 3) )/(y (2k -3) )
    = (2k + 3)/(2k-3) (1)
    Có : (2m+3n)/(2m-3n)
    = (2nk + 3n)/(2nk-3n)
    = (n (2k+3) )/(n (2k-3) )
    = (2k+3)/(2k-3) (2)
    Từ (1), (2)
    -> (2x+3y)/(2x-3y) = (2m+3n)/(2m-3n) (= (2k+3)/(2k-3) )
    -> đpcm

Leave a reply

222-9+11+12:2*14+14 = ? ( )