Toán Lớp 7: Bai1:a)2x.(x-1/7)=0
b)(x-1)mũ x+2=(x-1)mũ x+6
Mn làm giúp e với e cảm ơn
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Toán Lớp 7: Bai1:a)2x.(x-1/7)=0
b)(x-1)mũ x+2=(x-1)mũ x+6
Mn làm giúp e với e cảm ơn
Comments ( 2 )
=> \(\left[ \begin{array}{l}2x=0\\x-\dfrac{1}{7}=0\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=0\\x=\dfrac{1}{7}\end{array} \right.\)
Vậy x∈{0;1/7}
– Áp dụng : A.B=0=> \(\left[ \begin{array}{l}A=0\\B=0\end{array} \right.\)
b)(x-1)^(x+2) =(x-1)^(x+6)
=>x+2=x+6
=>x-x=6-2
=>0=4\text{ ( vô lí )
Vậy x∈∅
– Áp dụng : a^m =a^n =>m=nAA m;n