Toán Lớp 7: (2x + 3 . √x ) . (3x – 2 . √x ) . ( √x + 2 ) = 0
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Toán Lớp 7: (2x + 3 . √x ) . (3x – 2 . √x ) . ( √x + 2 ) = 0
Comments ( 1 )
x = 0\\
x = \dfrac{4}{9}
\end{array} \right.\)
DK:x \ge 0\\
\left( {2x + 3\sqrt x } \right)\left( {3x – 2\sqrt x } \right).\left( {\sqrt x + 2} \right) = 0\\
\to \sqrt x \left( {2\sqrt x + 3} \right).\sqrt x \left( {3\sqrt x – 2} \right).\left( {\sqrt x + 2} \right) = 0\\
\to x\left( {2\sqrt x + 3} \right)\left( {3\sqrt x – 2} \right).\left( {\sqrt x + 2} \right) = 0\\
\to \left[ \begin{array}{l}
x = 0\\
3\sqrt x – 2 = 0
\end{array} \right.\left( {do:\left\{ \begin{array}{l}
2\sqrt x + 3 > 0\\
\sqrt x + 2 > 0
\end{array} \right.\forall x \ge 0} \right)\\
\to \left[ \begin{array}{l}
x = 0\\
\sqrt x = \dfrac{2}{3}
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 0\\
x = \dfrac{4}{9}
\end{array} \right.
\end{array}\)