Ta có: |5-x|=5-x khi 5-xge0 =>xle5 |5-x|=-5+x khi 5-x<0=>x>5 Trường hợp 1:xle5 |5-x|=3x+1 =>5-x=3x+1 =>-x-3x=1-5 =>-4x=-4 =>x=-4:(-4) =>x=1(TMĐK:xle5) Trường hợp 2:x>5 |5-x|=3x+1 =>5-x=-(3x+1) =>5-x=-3x-1 =>-x+3x=-1-5 =>x.(-1+3)=-6 =>x.2=-6 =>x=-6:2 =>x=-3(KTMĐK:x>5) Vậy x=1
|5-x|=5-x khi 5-xge0 =>xle5
|5-x|=-5+x khi 5-x<0=>x>5
Trường hợp 1:xle5
|5-x|=3x+1
=>5-x=3x+1
=>-x-3x=1-5
=>-4x=-4
=>x=-4:(-4)
=>x=1(TMĐK:xle5)
Trường hợp 2:x>5
|5-x|=3x+1
=>5-x=-(3x+1)
=>5-x=-3x-1
=>-x+3x=-1-5
=>x.(-1+3)=-6
=>x.2=-6
=>x=-6:2
=>x=-3(KTMĐK:x>5)
Vậy x=1