Toán Lớp 6: Chứng minh rằng abc-cba chia hết cho 11 (a>c)
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Toán Lớp 6: Chứng minh rằng abc-cba chia hết cho 11 (a>c)
Comments ( 2 )
=100a+10b+c-(100c+10b+a)
=100a+10b+c-100c-10b-a
=(100a-a)-(100c-c)+(10b-10b)
=99a-99c+0
=99a-99c
=99(a-c)=9.11.(a-c)\vdots 11 AA a;c
=>\overline{abc}-\overline{cba}\vdots 11(đpcm)
Vậy \overline{abc}-\overline{cba}\vdots 11