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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Tìm nhân tử chung của: $\sqrt[]{42}$ – $\sqrt[]{30}$ + $\sqrt[]{21}$ – 2$\sqrt[]{6}$ – $\sqrt[]{15}$ – 2$\sqrt[]{3}$

Tháng Sáu 23, 2022 Toán học 1 Comment 0 views

Toán Lớp 9: Tìm nhân tử chung của:
$\sqrt[]{42}$ – $\sqrt[]{30}$ + $\sqrt[]{21}$ – 2$\sqrt[]{6}$ – $\sqrt[]{15}$ – 2$\sqrt[]{3}$

Comments ( 1 )

  1. quynhthanhnghi
    quynhthanhnghi
    23 Tháng Sáu, 2022 at 12:03 sáng
    Reply
    \sqrt{42}-\sqrt{30}+\sqrt{21}-2\sqrt{6}-\sqrt{15}-2\sqrt{3}
    =\sqrt{42}-\sqrt{30}+\sqrt{21}-\sqrt{24}-\sqrt{15}-\sqrt{12}
    =\sqrt{3}.\sqrt{14}-\sqrt{3}.\sqrt{10}+\sqrt{3}.\sqrt{7}-\sqrt{3}.\sqrt{8}-\sqrt{3}.\sqrt{5}-\sqrt{3}.\sqrt{4}
    =\sqrt{3}.(\sqrt{14}-\sqrt{10}+\sqrt{7}-\sqrt{8}-\sqrt{5}-\sqrt{4})
    =\sqrt{3}.[(\sqrt{14}-\sqrt{10}-\sqrt{8}-\sqrt{4})+\sqrt{7}-\sqrt{5}]
    =\sqrt{3}.[\sqrt{2}.(\sqrt{7}-\sqrt{5}-\sqrt{4}-\sqrt{2})+\sqrt{7}-\sqrt{5}]
    =\sqrt{3}.[\sqrt{2}.(\sqrt{7}-\sqrt{5}-2-\sqrt{2})+\sqrt{7}-\sqrt{5}]
     

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222-9+11+12:2*14+14 = ? ( )

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