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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: a,b,c >0 a+b+c=3 Tìm Min B=1/a +1/4b +1/9c Ai giúp em vớiii

Toán Lớp 9: a,b,c >0 a+b+c=3
Tìm Min B=1/a +1/4b +1/9c
Ai giúp em vớiii

Comments ( 1 )

  1. Giải đáp: $B\ge \dfrac{121}{108}$
    Lời giải và giải thích chi tiết:
    Ta có:
    $B=\dfrac1a+\dfrac1{4b}+\dfrac1{9c}$
    $\to B=\dfrac{1^2}{a}+\dfrac{(\dfrac12)^2}b+\dfrac{(\dfrac13)^2}{c}$
    $\to B\ge \dfrac{(1+\dfrac12+\dfrac13)^2}{a+b+c}$
    $\to B\ge \dfrac{\dfrac{121}{36}}{3}$
    $\to B\ge \dfrac{121}{108}$
    Dấu = xay ra khi:
    $\dfrac1a=\dfrac{\dfrac12}b=\dfrac{\dfrac13}c=\dfrac{1+\dfrac12+\dfrac13}{a+b+c}=\dfrac{11}{18}$
    $\to a=\dfrac{18}{11}, b=\dfrac9{11}, c=\dfrac6{11}$

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222-9+11+12:2*14+14 = ? ( )