Toán học 20 Tháng Hai, 2023 No Comments By Bảo Châu Toán Lớp 9: -4x – 9 √x + 3/x + 3√x +2 + √x – 1/ √x+1 – 2 √x -1/ √x+2
#AkaShi (-4x-9\sqrt{x}+3)/(x+3\sqrt{x}+2)+(\sqrt{x}-1)/(\sqrt{x}+1)-(2\sqrt{x}-1)/(\sqrt{x}+2) Đk: x >= 0 =(-4x-9\sqrt{x}+3)/(x+2\sqrt{x}+\sqrt{x}+2)+(\sqrt{x}-1)/(\sqrt{x}+1)-(2\sqrt{x}-1)/(\sqrt{x}+2) =(-4x-9\sqrt{x}+3)/((\sqrt{x}+1)(\sqrt{x}+2))+(\sqrt{x}-1)/(\sqrt{x}+1)-(2\sqrt{x}-1)/(\sqrt{x}+2) =(-4x-9\sqrt{x}+3)/((\sqrt{x}+1)(\sqrt{x}+2))+((\sqrt{x}-1)(\sqrt{x}+2))/((\sqrt{x}+1)(\sqrt{x}+2))-((2\sqrt{x}-1)(\sqrt{x}+1))/((\sqrt{x}+1)(\sqrt{x}+2)) =(-4x-9\sqrt{x}+3+x+\sqrt{x}-2-2x-\sqrt{x}+1)/((\sqrt{x}+1)(\sqrt{x}+2)) =(-5x-9\sqrt{x}+2)/((\sqrt{x}+1)(\sqrt{x}+2)) =(-5x-10\sqrt{x}+\sqrt{x}+2)/((\sqrt{x}+1)(\sqrt{x}+2)) =((\sqrt{x}+2)(-5\sqrt{x}+1))/((\sqrt{x}+1)(\sqrt{x}+2)) =(-5\sqrt{x}+1)/(\sqrt{x}+1) Trả lời
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