Toán Lớp 8: tính
$\frac{1}{2}$ $x^{2}$ y (2$x^{3}$ -$\frac{2}{5}$ x$y^{2}$ – 1 )
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Toán Lớp 8: tính
$\frac{1}{2}$ $x^{2}$ y (2$x^{3}$ -$\frac{2}{5}$ x$y^{2}$ – 1 )
Comments ( 2 )
1/2x^2y.(2x^3-2/5xy^2-1)
=1/2x^2y.2x^3-1/2x^2y . 2/5xy^2-1/2x^2y.1
=x^5y-1/5x^3y^3-1/2x^2y
Giải đáp:
$\dfrac{1}{2}x^2y.(2x^3-\dfrac{2}{5}xy^2-1)$
$= \dfrac{1}{2}x^2y.2x^3-\dfrac{1}{2}x^2y.\dfrac{2}{5}xy^2-\dfrac{1}{2}x^2y.1$
$= x^5y-\dfrac{1}{5}x^3y^3-\dfrac{1}{2}x^2y$