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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tính: a. A=(2+1)(2^2+1)(2^4+1)-. (2^32+1)-2^64 b. B= (5+3)(5^2+3^2)(5^4+3^4)…(5^64+3^64)+5^128-3^128/2

Tháng Mười Hai 6, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: Tính:
a. A=(2+1)(2^2+1)(2^4+1)….. (2^32+1)-2^64
b. B= (5+3)(5^2+3^2)(5^4+3^4)…(5^64+3^64)+5^128-3^128/2

Comments ( 2 )

  1. daithanh
    daithanh
    6 Tháng Mười Hai, 2022 at 1:17 chiều
    Reply
    a)
    A = (2 + 1)(2^2 + 1)(2^4 + 1)…………..(2^32 + 1) – 2^64
    A = (2 – 1)(2 + 1)(2^2 + 1)(2^4 + 1)…………..(2^32 + 1) – 2^64
    A = (2^2 – 1)(2^2 + 1)(2^4 + 1)…………..(2^32 + 1) – 2^64
    A = (2^32 – 1)(2^32 + 1) – 2^64
    A = 2^64 – 1 – 2^64
    A = -1
    b)
    B = (5 + 3)(562 + 3^2)(5^4 + 3^4)…………(5^64 + 3^64) + (5^128 – 3^128)/2
    B = ((5 – 3)(5 + 3)(5^2 + 3^2)(5^4 + 3^4)…………(5^64 + 3^64))/2 + (5^128 – 3^128)/2
    B = ((5^2 – 3^2)(5^2 + 3^2)(5^4 + 3^4)…………(5^64 + 3^64) + 5^128 – 3^128)/2
    B = ((5^64 – 3^64)(5^64 + 3^64) + 5^128 – 3^128)/2
    B = (2 . 5^128)/2
    B = 5^128

  2. lanminhngoc
    lanminhngoc
    6 Tháng Mười Hai, 2022 at 1:16 chiều
    Reply
    Giải đáp:
    a)A=-1
    b)B=5^128-3^128
    Lời giải và giải thích chi tiết:
    a)A=(2+1)(2²+1)(2^4+1)…(2^32+1)-2^64
    =1.(2+1)(2²+1)(2^4+1)…(2^32+1)-2^64
    =(2-1)(2+1)(2²+1)(2^4+1)…(2^32+1)-2^64
    =(2²-1)(2²+1)(2^4+1)…(2^32+1)-2^64
    =[(2^2)^2-1^2](2^4+1)…(2^32+1)-2^64
    =(2^4-1)(2^4+1)…(2^32+1)-2^64
    =[(2^4)^2-1^2]…(2^32+1)-2^64
    =(2^8-1)…(2^32+1)-2^64
    =(2^32-1)(2^32+1)-2^64
    =(2^32)^2-1^2-2^64
    =2^64-1-2^64
    =-1
    b)B=(5+3)(5²+3²)(5^4+3^4)…(5^64+3^64)+(5^128-3^128)/2
    =[2(5+3)(5²+3²)(5^4+3^4)…(5^64+3^64)]/2+(5^128-3^128)/2
    =[2(5+3)(5²+3²)(5^4+3^4)…(5^64+3^64)+5^128-3^128)/2
    =[(5-3)(5+3)(5²+3²)(5^4+3^4)…(5^64+3^64)+5^128-3^128)/2
    =[(5^2-3^2)(5²+3²)(5^4+3^4)…(5^64+3^64)+5^128-3^128)/2
    =[[(5^2)^2-(3^2)^2](5^4+3^4)…(5^64+3^64)+5^128-3^128)/2
    =[(5^4-3^4)(5^4+3^4)…(5^64+3^64)+5^128-3^128)/2
    =[[(5^4)^2-(3^4)^2]…(5^64+3^64)+5^128-3^128)/2
    =[(5^8-3^8)…(5^64+3^64)+5^128-3^128)/2
    =[(5^64-3^64)(5^64+3^64)+5^128-3^128)/2
    =[(5^64)^2-(3^64)^2+5^128-3^128)/2
    =[5^128-3^128+5^128-3^128)/2
    =[2(5^128-3^128)]/2
    =5^128-3^128

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222-9+11+12:2*14+14 = ? ( )

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