Toán Lớp 8: Tìm x, biết
(6x^2+2x)(x+1)+(x-1)(6x^2+2x)=0
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Toán Lớp 8: Tìm x, biết
(6x^2+2x)(x+1)+(x-1)(6x^2+2x)=0
Comments ( 2 )
$⇒(6x^2+2x)(x+1+x-1)=0$
$⇒4x^2(3x+1)=0$
$⇔4x^2=0$ hoặc $3x+1=0$
$x=0$ $x=\dfrac{-1}{3}$
Vậy S={0,\frac{-1}{3}}