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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x biết (x^2-4x)-8(x^2-4x)+15=0

Toán Lớp 8: Tìm x biết (x^2-4x)-8(x^2-4x)+15=0

Comments ( 2 )

  1. (x²-4x)-8(x²-4x)+15=0
    (x²-4x)-8(x²-4x)+16-1=0
    ⇔(x²-4x+4)²-1=0
    ⇔(x²-4x+4-1)(x²-4x+4+1)=0
    ⇔(x²-4x+3)(x²-4x+5)=0
    x²-4x+3=0 hoặc x²-4x+5=0

  2. (x^2-4x)-8(x^2-4x)+15=0(1)
    Đặt: x^2-4x=a, khi đó ta có:
    a^2-8a+15=0
    <=>a^2-3a-5a+15=0
    <=>a(a-3)-5(a-3)=0
    <=>(a-3)(a-5)=0
    <=>[(a-3=0),(a-5=0):}(1)
    Quay lại x, ta có:
    (1)
    <=>[(x^2-4x-3=0),(x^2-4x-5=0):}
    <=>[(x=2+-\sqrt{7}),(x=-1),(x=5):}
    Vậy x=2+-\sqrt{7};x=-1;x=5

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222-9+11+12:2*14+14 = ? ( )