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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x ( 2x – 1 )^2 – ( 4x + 1 ) . ( x – 3 ) = -3

Home/ Toán Lớp 8: Tìm x ( 2x – 1 )^2 – ( 4x + 1 ) . ( x – 3 ) = -3

Toán Lớp 8: Tìm x ( 2x – 1 )^2 – ( 4x + 1 ) . ( x – 3 ) = -3

Tháng Tám 5, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: Tìm x
( 2x – 1 )^2 – ( 4x + 1 ) . ( x – 3 ) = -3

Comments ( 2 )

  1. buithaianh98
    buithaianh98
    5 Tháng Tám, 2022 at 9:20 chiều
    Reply
    (2x – 1)^2 – (4x + 1) . (x – 3) = -3
    4x^2 – 4x + 1 – (4x^2 – 12x + x – 3) = -3
    4x^2 – 4x + 1 – 4x^2 + 12x – x + 3 = -3
    (4x^2 – 4x^2) + (-4x + 12x – x) + 4 = -3
    7x + 4 = -3
    7x = -7
    x = -1
    Vậy x = -1
    Gửi bạn nha
     

  2. cobexinhdep
    cobexinhdep
    5 Tháng Tám, 2022 at 9:20 chiều
    Reply
    ~ Bạn tham khảo ~
    (2x-1)^2 – (4x+1)(x-3)=-3
    <=> 4x^2 – 4x + 1 – 4x^2 + 12x – x + 3 + 3 = 0
    <=> 7x+7=0
    <=> 7x=-7
    <=> x=-1
    Vậy x=-1

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222-9+11+12:2*14+14 = ? ( )

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