Toán Lớp 8: Phân tích : (x-1)(x-2)(x-4)(x-5)-28
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Toán Lớp 8: Phân tích : (x-1)(x-2)(x-4)(x-5)-28
Comments ( 2 )
\quad (x-1)(x-2)(x-4)(x-5) – 28\\
= [(x-1)(x-5)][(x-2)(x-4)] – 28\\
= (x^2 – 6x + 5)(x^2 – 6x + 8) – 28\\
= (x^2 – 6x)^2 + 13(x^2- 6x) + 22\\
= (x^2 – 6x)^2 + 11(x^2- 6x) + 2(x^2 – 6x) + 22\\
= (x^2 – 6x)(x^2 – 6x + 11) + 2(x^2 – 6x + 11)\\
= (x^2 – 6x + 11)(x^2 – 6x + 2)
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