Toán Lớp 8: k) x^2 + 1 – $\frac{x^4 + 1}{x^2 + 1}$
l) $\frac{11x}{2x – 3}$ – $\frac{x – 18}{3-2x}$
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Toán Lớp 8: k) x^2 + 1 – $\frac{x^4 + 1}{x^2 + 1}$
l) $\frac{11x}{2x – 3}$ – $\frac{x – 18}{3-2x}$
Comments ( 2 )
k,x²+1−x4+1x²+1k,x²+1-x4+1x²+1
=(x2+1)²x²+1−x4+1x²+1
=x4+2×2+1x²+1−x4+1x²+1
=2x²x²+1
l)11x2x−3−x−183−2xl)11x2x-3-x-183-2x(x(x≠≠1.5)1.5)
=−11×3−2x−x−183−2x=-11×3-2x-x-183-2x
=−12x+183−2x
=6(3−2x)3−2×6(3−2x)3−2x
=6