Toán Lớp 8: $\frac{2}{x-3}$ + $\frac{1-5x}{x^2-9}$ + $\frac{3}{x+3}$
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Toán Lớp 8: $\frac{2}{x-3}$ + $\frac{1-5x}{x^2-9}$ + $\frac{3}{x+3}$
Comments ( 2 )
2/(x-3)+(1-5x)/(x^2-9)+3/(x+3)(xne+-3)
=2/(x-3)+(1-5x)/((x-3)(x+3))+3/(x+3)
=(2(x+3)+1-5x+3(x-3))/((x-3)(x+3))
=(2x+6+1-5x+3x-9)/((x-3)(x+3))
=(-2)/(x^2-9)
Mong cho lời giải hay nhất ❤️⭐️
