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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: a) $(x – 4) ^{2}$ – 36 = 0 b) 5(x + 3) – 2x ( 3 +x) = 0 c) x ( x- 5) – 4x + 20 = 0

Toán Lớp 8: a) $(x – 4) ^{2}$ – 36 = 0
b) 5(x + 3) – 2x ( 3 +x) = 0
c) x ( x- 5) – 4x + 20 = 0

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
    $a)(x-4)^2-36=0\\(x-4)^2=6^2$<=>\(\left[ \begin{array}{l}x-4=6\\x-4=-6\end{array} \right.\) <=>\(\left[ \begin{array}{l}x=10\\x=-2\end{array} \right.\) 
    $b) 5(x + 3) – 2x ( 3 +x) = 0\\(3+x)(5-2x)=0$<=>\(\left[ \begin{array}{l}3+x=0\\5-2x=0\end{array} \right.\) <=>\(\left[ \begin{array}{l}x=-3\\x=\dfrac52\end{array} \right.\)
    $c) x ( x- 5) – 4x + 20 = 0\\x ( x- 5) – 4(x-5) = 0\\(x-5)(x-4)=0$<=>\(\left[ \begin{array}{l}x-5=0\\x-4=0\end{array} \right.\) <=>\(\left[ \begin{array}{l}x=5\\x=4\end{array} \right.\)

  2. a, (x-4)^2-36=0
    (x-4)^2-6^2=0
    (x-4-6)(x-4+6)=0
    (x-10)(x+2)=0
    TH1
    x-10=0
    x=10
    TH2
    x+2=0
    x=-2
    b, 5.(x+3)-2x(3+x)=0
    5.(x+3)-2x.(x+3)=0
    (x+3)(5-2x)=0
    TH1
    x+3=0
    x=-3
    TH2
    5-2x=0
    2x=5
    x=5/2
    c, x.(x-5)-4x+20=0
    x.(x-5)-4.(x-5)=0
    (x-5)(x-4)=0
    TH1
    x-5=0
    x=5
    TH2
    x-4=0
    x=4
    Cho mk xin hay nhất please
    Thank you

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222-9+11+12:2*14+14 = ? ( )