Toán Lớp 8: 1)Phân thức thành nhân tử
C=(2x+3)^2-(x^2-6x+9)
D=x^2-16y^2+5x+20y
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Toán Lớp 8: 1)Phân thức thành nhân tử
C=(2x+3)^2-(x^2-6x+9)
D=x^2-16y^2+5x+20y
Comments ( 2 )
$C=(2x+3)^2-(x-3)^2$
$C=(2x+3+x-3)(2x+3-x+3)$
$C=3x(x+6)$
$D=x^2-16y^2+5x+20y$
$D=(x+4y)(x-4y)+5(x+4y)$
$D=(x+4y)(x-4y+5)$