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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: (x-1)^2 – (x+3)(x+2) = 3(x-2)-(x+5) x^2 – x = 2 giải giúp mik vs ah cho 5 sao

Toán Lớp 8: (x-1)^2 – (x+3)(x+2) = 3(x-2)-(x+5)
x^2 – x = 2
giải giúp mik vs ah cho 5 sao

Comments ( 2 )

  1. Giải đáp:
    a) x = 2/3
    b) x = 2 ; x = – 1
    Lời giải và giải thích chi tiết:
    a)
    (x – 1)^2 – (x + 3)(x + 2) = 3(x – 2) – (x + 5)
    (x^2 – 2.x.1 + 1^2) – (x^2 + 2x + 3x + 6) = 3x – 6 – x – 5
    (x^2 – 2x + 1) – (x^2 + 5x + 6)  = 2x – 11
    x^2 – 2x + 1 – x^2 – 5x – 6 – 2x + 11 = 0
    (x^2 – x^2) – (2x + 2x + 5x) + (1 – 6 + 11) = 0
    – 9x + 6 = 0
    – 3(3x – 2) = 0
    => 3x – 2 = 0
    => x = 2/3
    Vậy x = 2/3
    ———————————————-
    b)
    x^2 – x = 2
    x^2 – x – 2= 0
    x^2 – 2x + x – 2 = 0
    (x^2 – 2x) + (x – 2) = 0
    x(x – 2) + (x – 2) = 0
    (x – 2)(x + 1) = 0
    => [(x – 2 = 0),(x + 1 = 0):}
    => [(x = 2),(x = – 1):}
    Vậy x = 2 ; x = – 1
    #SunHee

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     (x-1)^2 -(x+3)(x+2)=2(x-2)-(x+5)
    =>x^2 -2x+1-x^2 -3x-2x-6=2x-4-x-5
    =>-7x-6-2x+x=-9
    =>-8x=-9+6
    =>-8x=-3
    =>x=3/8
    x^2 -x=2
    =>x^2 -x-2=0
    =>x^2 -2x+x-2=0
    =>x(x-2)+(x-2)=0
    =>(x-2)(x+1)=0
    =>\(\left[ \begin{array}{l}x-2=0\\x+1=0\end{array} \right.\) $\\$=>\(\left[ \begin{array}{l}x=2\\x=-1\end{array} \right.\)$\\$Vậy x in {-1;2} 

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222-9+11+12:2*14+14 = ? ( )