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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm `x` `h)“|-2:x+5/6|=3/4` `i)` `|(-2/3)*x+3/8|*(-8/5)=-8/15`

Toán Lớp 7: Tìm x
h)|-2:x+5/6|=3/4
i) |(-2/3)*x+3/8|*(-8/5)=-8/15

Comments ( 1 )

  1. h) |-2 : x + 5/6| = 3/4
    =>\(\left[ \begin{array}{l}-2 : x+ \dfrac{5}{6}=\dfrac{3}{4}\\2:x+ \dfrac{5}{6}= \dfrac{3}{4}\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}-2 : x=\dfrac{3}{4}- \dfrac{5}{6}\\-2 : x=\dfrac{-3}{4}- \dfrac{5}{6}\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}-2 : x=\dfrac{-1}{12}\\-2 : x=\dfrac{-19}{12}\end{array} \right.\) 
    =>\(\left[ \begin{array}{l} x=-2 : \dfrac{-1}{12}\\ x=-2 : \dfrac{-19}{12}\end{array} \right.\) 
    =>\(\left[ \begin{array}{l} x=24\\ x=\dfrac{24}{19}\end{array} \right.\) 
    Vậy x \in { 24 ; 24/19}
    i) |(-2/3) . x + 3/8| . (-8/5) = -8/15
    |(-2/3) . x + 3/8| = -8/15 : (-8)/5
    |(-2/3) . x + 3/8| = 1/3
    =>\(\left[ \begin{array}{l} \dfrac{-2}{3}x+ \dfrac{3}{8}=\dfrac{1}{3}\\  \dfrac{-2}{3}x+ \dfrac{3}{8}=\dfrac{-1}{3}\end{array} \right.\) 
    =>\(\left[ \begin{array}{l} \dfrac{-2}{3}x =\dfrac{1}{3}- \dfrac{3}{8}\\ \dfrac{-2}{3}x=\dfrac{-1}{3}- \dfrac{3}{8}\end{array} \right.\)
    =>\(\left[ \begin{array}{l} \dfrac{-2}{3}x =\dfrac{-1}{24}\\ \dfrac{-2}{3}x=\dfrac{-17}{24}\end{array} \right.\)
    =>\(\left[ \begin{array}{l} x =\dfrac{-1}{24} : \dfrac{-2}{3}\\ x=\dfrac{-17}{24} : \dfrac{-2}{3}\end{array} \right.\)
    =>\(\left[ \begin{array}{l} x =\dfrac{1}{16}\\ x=\dfrac{17}{16} \end{array} \right.\)
    Vây x \in { 1/16 ; 17/16}
    #caty09

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222-9+11+12:2*14+14 = ? ( )