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Toán Lớp 7: |x+5|-6=9 $\frac{2}{3}$ + $\frac{5}{3}$x = $\frac{5}{7}$

Home/ Toán Lớp 7: |x+5|-6=9 $\frac{2}{3}$ + $\frac{5}{3}$x = $\frac{5}{7}$

Toán Lớp 7: |x+5|-6=9 $\frac{2}{3}$ + $\frac{5}{3}$x = $\frac{5}{7}$

Linh Tháng Ba 14, 2023 Toán học 0 Comments 0 views

Toán Lớp 7: |x+5|-6=9
$\frac{2}{3}$ + $\frac{5}{3}$x = $\frac{5}{7}$

Comments ( 2 )

haiyemy
14 Tháng Ba, 2023 at 10:15 sáng

Reply

Lời giải chi tiết:

a) |x+5|-6=9

=>|x+5|=9+6

=>|x+5|=15

=>\(\left[ \begin{array}{l}x+5=15\\x+5=-15\end{array} \right.\)

=>\(\left[ \begin{array}{l}x=10\\x=-20\end{array} \right.\)

Vậy x=10 hoặc x=-20

b) 2/3+5/3x=5/7

=>5/3x=5/7-2/3

=>5/3x=1/21

=>x=1/21:5/3

=>x=1/35

Vậy x=1/35
quynhthanhnhu
14 Tháng Ba, 2023 at 10:14 sáng

Reply

Bài làm:

a, |x + 5| – 6 = 9

<=> |x + 5| = 15

<=> $\left[\begin{matrix} x + 5 = 15\\ x + 5 = -15\end{matrix}\right.$

<=> $\left[\begin{matrix} x = 10\\ x = -20\end{matrix}\right.$

b, $\dfrac{2}{3}$ + $\dfrac{5}{3}$ x = $\dfrac{5}{7}$

<=> $\dfrac{5}{3}$ x = $\dfrac{5}{7}$ – $\dfrac{2}{3}$

<=> $\dfrac{5}{3}$ x = $\dfrac{15}{21}$ – $\dfrac{14}{21}$

<=> $\dfrac{5}{3}$ x = $\dfrac{1}{21}$

<=> x = $\dfrac{3}{105}$

<=> x = $\dfrac{1}{35}$

@Enk

#BTS

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