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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: | 3x – 1/9 | – 2/81 = [(1/3)^2]^3 : ( 1/3)^2

Home/ Toán Lớp 7: | 3x – 1/9 | – 2/81 = [(1/3)^2]^3 : ( 1/3)^2

Toán Lớp 7: | 3x – 1/9 | – 2/81 = [(1/3)^2]^3 : ( 1/3)^2

Tháng Ba 14, 2023 Toán học 2 Comments 0 views

Toán Lớp 7: | 3x – 1/9 | – 2/81 = [(1/3)^2]^3 : ( 1/3)^2

Comments ( 2 )

  1. buianhtuan
    buianhtuan
    14 Tháng Ba, 2023 at 2:38 sáng
    Reply
    Giải đáp và Lời giải và giải thích chi tiết:
    ${| 3x – \dfrac1 9 |-}$ $\dfrac{2}{81}=$ $ [(\dfrac{1}{3})^2]^3:$ $(\dfrac{1}{3})^2$
    $=|3x-\dfrac{1}{9}|-$ $\dfrac{2}{81}=$ $\dfrac{(\frac{1}{3})^6}{(\frac{1}{3})^2}$
    $=|3x-\dfrac{1}{9}|-$ $\dfrac{2}{81}=$ $(\dfrac{1}{3})^4$
    $=|3x-\dfrac{1}{9}|-$ $\dfrac{2}{81}$ $=\dfrac{1}{81}$
    $=|3x-\dfrac{1}{9}|-$ $\dfrac{2}{81}-$ $\dfrac{1}{81}=0$
    $=|3x-\dfrac{1}{9}|-$ $\dfrac{1}{27}=0$
    $=|3x-\dfrac{1}{9}|=$ $\dfrac{1}{27}$
    $3x-\dfrac{1}{9}=$ $\dfrac{1}{27}$
    $3x-\dfrac{1}{9}=$ $-\dfrac{1}{27}$
    $3x=\dfrac{4}{27}$
    $3x=\dfrac{2}{27}$
    $x=\dfrac{4}{81}$
    $x=\dfrac{2}{81}$ 
    #ThiênShi

  2. quynhthanhnghi
    quynhthanhnghi
    14 Tháng Ba, 2023 at 2:38 sáng
    Reply
    Giải đáp:
    | 3x – 1/9 | – 2/81 = [(1/3)^2]^3 : ( 1/3)^2
    | 3x – 1/9 | – 2/81 = (1/3)^6 : (1/3)^2
    | 3x – 1/9 | – 2/81 = (1/3)^4
    | 3x – 1/9 | – 2/81 = 1/81
    | 3x – 1/9 | = 1/81 + 2/81 = 3/81
    | 3x – 1/9 | = 1/27
    -> Ta chia 2 trường hợp :
    Th1 : 3x – 1/9 = 1/27
    -> 3x = 4/27
    -> x = 4/81
    Th2 : 3x – 1/9 = -1/27
    3x = 2/27
    -> x = 2/81
    Vậy x in { 4/81 ; 2/81 }

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222-9+11+12:2*14+14 = ? ( )

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