Toán Lớp 6: Tìm x ∈ N
1 + 3 + 5 + … + 99 = ( x – 2 )^2
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Toán Lớp 6: Tìm x ∈ N
1 + 3 + 5 + … + 99 = ( x – 2 )^2
Comments ( 2 )
⇒ ( 99 + 1).[(99 – 1) : 2 + 1] : 2 = (x – 2)^2
⇒ 100.50 : 2 = (x – 2)^2
⇒ 2500 = (x – 2)^2
⇒ 50^2 = (x – 2)^2
⇒ x – 2 = 50 hoặc x – 2 = -50
=> x = 52 hoặc x = -48
Vậy . . .