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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm BC của BC(30,105) BC(84,108) BC(98,72,42) BC(68,208,100)

Toán Lớp 6: Tìm BC của
BC(30,105)
BC(84,108)
BC(98,72,42)
BC(68,208,100)

Comments ( 2 )

  1. BC (30,105) là : 210
    BC (84,108) là : 756
    BC (98,72,42) là: 3528
    BC (68,208,100) là : 88400

  2. BC_(30 ; 105)
    30 = 2 . 3 . 5 ; 105 = 3 . 5 . 7
    BCNNN_(30 ; 105) = 2 . 3 . 5 . 7 = 210
    ⇒ BC_(30 ; 105) = B_(210) = {0 ; 210 ; 420 ; ……….}
    BC_(84 ; 108)
    84 = 2^2 . 3 . 7 ; 108 = 2^2 . 3^3
    BCNNN_(30 ; 105) = 2^2 . 3^3 . 7 = 756
    ⇒ BC_(84 ; 108) = B_(756) = {0 ; 756 ; ………..}
    BC_(98 ; 72 ; 42)
    98 = 2 . 7^2 ; 72 = 2^3 . 3^2 ; 42 = 2 . 3 . 7
    BCNNN_(98 ; 72 ; 42) = 2^3 . 3^2 . 7^2 = 3528
    ⇒ BC_(98 ; 72 ; 42) = B_(3528) = {0 ; 3528 ; …………}
    BC_(68 ; 208 ; 100)
    68 = 2^2 . 17 ; 208 = 2^4 . 13 ; 100 = 2^2 . 5^2
    BCNNN_(68 ; 208 ; 100) = 2^4 . 13 . 17 . 5^2 = 88400
    ⇒ BC_(68 ; 208 ; 100) = B_(88400) = {0 ; 88400 ; ………..}

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222-9+11+12:2*14+14 = ? ( )