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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: i, 5^x+4 – 3.5^x+3=2.5^11 k, 3^x+2 + 4.3^x+1=7.3^6 l, 27<81^3 : 3^x<243 (x ∈ N)

Toán Lớp 6: i, 5^x+4 – 3.5^x+3=2.5^11
k, 3^x+2 + 4.3^x+1=7.3^6
l, 27<81^3 : 3^x<243 (x ∈ N)

Comments ( 2 )

  1. \text{i)}
    5^{x+4} – 3 . 5^{x+3} = 2 . 5^11
    -> 5^{x+3} . 5 – 3 . 5^{x+3} = 2 . 5^11
    -> 5^{x+3}(5 -3) = 2 . 5^11
    -> 5^{x+3} . 2 = 2 . 5^11
    -> 5^{x+3} =5^11
    -> x +3=11
    -> x = 8
    Vậy x = 8
    $\\$
    \text{k)}
    3^{x+2} + 4 . 3^{x+1} = 7 . 3^6
    -> 3^{x+1} . 3 + 4 . 3^{x+1} = 7 . 3^6
    -> 3^{x+1}(3+4) = 7 . 3^6
    -> 3^{x+1} = 3^6
    -> x +1 =6
    -> x =5
    Vậy x =5
    $\\$
    \text{l)}
    27 < 81^3 : 3^x < 243
    -> 3^3 < 3^4 : 3^x < 3^5
    -> 3^4 : 3^x = 3^4
    -> 3^{4 -x} =3^4
    ->  4 – x = 4
    -> x = 0
    Vậy x =0

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222-9+11+12:2*14+14 = ? ( )