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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: C= 3+ $3^{2}$ + $3^{3}$ +-.+ $3^{2019}$ + $3^{2020}$ Tìm x để: 2C + 3= $3^{x+2}$

Toán Lớp 6: C= 3+ $3^{2}$ + $3^{3}$ +…..+ $3^{2019}$ + $3^{2020}$
Tìm x để: 2C + 3= $3^{x+2}$

Comments ( 2 )

  1. C = 3 + 3^2 + 3^3 + ….. + 3^2019 + 3^2020
    3C = 3 . (3 + 3^2 + 3^3 + ….  + 3^2019 + 3^2020)
    3C = 3^2 + 3^3 + 3^4 + ….. + 3^2020 + 3^2021
    3C – C = (3^2 + 3^3 + 3^4 + ….. + 3^2020 + 3^2021) – (3 + 3^2 + 3^3 + …. + 3^2019 + 3^2020)
    2C = 3^2 + 3^3 + 3^4 + ….. + 3^2020 + 3^2021 – 3 – 3^2 – 3^3 – …. – 3^2019 – 3^2020
    2C = 3^2021 – 3
    => 2C + 3 = 3^2021
    Mà 2C + 3 = 3^(x + 2)
    => 3^(x + 2) = 3^2021
    => x + 2 = 2021
    => x = 2019
    Vậy x = 2019
     

  2. Giải đáp+Lời giải và giải thích chi tiết:
    Ta có:
    C=3+3^2+3^3+…+3^2019+3^2020
    3C=3^2+3^3+3^4+…+3^2020+3^2021
    3C-C=(3^2+3^3+3^4+…+3^2020+3^2021)-(3+3^2+3^3+…+3^2019+3^2020)
    2C=3^2021-3
    =>2C+3=3^(x+2)=3^2021-3+3=3^2021
    =>3^2021=3^(x+2)
    =>x+2=2021
    =>x=2021-2=2019
    Vậy x=2019

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222-9+11+12:2*14+14 = ? ( )