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222-9+11+12:2*14+14 = ? ( )

## Toán Lớp 6: a) ( – 125) – ( – 98) b) ( – 96) +( -115) + ( -104) + 15 c) ( – 12) . 56 + 12.( -44) – 50 d) 1997- [ 10.( 4 mũ 3 – 56) : 2 mũ 3 + 2

Toán Lớp 6: a) ( – 125) – ( – 98)
b) ( – 96) +( -115) + ( -104) + 15
c) ( – 12) . 56 + 12.( -44) – 50
d) 1997- [ 10.( 4 mũ 3 – 56) : 2 mũ 3 + 2 mũ 3 ]. ( – 2005) mũ 0

## Comments ( 2 )

1. a. (-125) – (-98)
=-125 + 98
=-27
b.  (-96) + (-115) + (-104) + 15
= (-211) + (-104) + 15
= (-315) + 15
= -310
c. (-12). 56 + 12.(-44) – 50
= -12. (56 + 44) – 50
= -12. 100 – 50
= -1200 – 50
= -1250
d/ 1997 – [10. ($4^{3}$ – 56) : $2^{3}$ +$2^{3}$ ]. ($(-2005)^{0}$
= 1979

2. $\text{a/ (-125) – (-98)}$ $\\$ $\text{= (-125) + 98}$ $\\$ $\text{= -27}$ $\\$ $\text{b/ (-96) + (-115) + (-104) + 15}$ $\\$ $\text{= (-211) + (-104) + 15}$ $\\$ $\text{= (-315) + 15}$ $\\$ $\text{= -310}$ $\\$ $\text{c/ (-12). 56 + 12.(-44) – 50 }$ $\\$ $\text{= -12. (56 + 44) – 50}$ $\\$ $\text{= -12. 100 – 50}$ $\\$ $\text{= -1200 – 50}$ $\\$ $\text{= -1250}$ $\\$ $\text{d/ 1997 – [10. ($4^{3}$– 56) :$2^{3}$+$2^{3}$].$(-2005)^{0}$}$ $\\$ $\text{= 1997 – [10. (64 – 56) : 8 + 8]. 1}$ $\\$ $\text{= 1997 – (10. 8 : 8 + 8)}$ $\\$ $\text{= 1997 – (80 : 8 + 8)}$ $\\$ $\text{= 1997 – (10 + 8)}$ $\\$ $\text{= 1997 – 18}$ $\\$ $\text{= 1979}$