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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: (3.(-4)).2²=64 UCLN(12;18) BCNN(24;36;72)

Toán Lớp 6: (3.(-4)).2²=64
UCLN(12;18)
BCNN(24;36;72)

Comments ( 2 )

  1. a,
    Ta có:
    12 = 2^2 · 3
    18 = 2 · 3^2
    => ƯCLN(12, 18) = 2 · 3 = 6
    b,
    Ta có:
    24 = 2^3 · 3
    36 = 2^2 · 3^2
    72 = 2^3 · 3^2
    => $BCNN(24, 36, 72)$ = 2^3 · 3^2 = 72
     

  2. 1) Ta có :
    12 = 2^2 * 3
    18 = 2 * 3^2
    ⇒ UCLN ( 12;18 ) = 2 * 3 = 6
    Vậy UCLN ( 12;18 ) = 6
    2) Ta có :
    72 vdots 24 ; 72 vdots 36
    ⇒ BCNNNN ( 24;36;72 ) = 72
    Vậy BCNNNN ( 24;36;72 ) = 72

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222-9+11+12:2*14+14 = ? ( )