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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 12: tìm m để y= |-$x^{4}$+8 $x^{2}$ +m| thuộc [-1;3] bằng có Min bằng 2018

Toán Lớp 12: tìm m để y= |-$x^{4}$+8 $x^{2}$ +m| thuộc [-1;3] bằng có Min bằng 2018

Comments ( 2 )

  1. Giải đáp:
     m∈{-2034;2027}
    Lời giải và giải thích chi tiết:
    y=|-x^4+8x^2+m|
    \text(TXĐ: D=R)
    \text( Đặt f(x))=-x^4+8x^2+m
    f'(x)=-4x^3+16x
    f'(x)=0<=>-4x^3+16x=0
    <=>-4x.(x^2-4)=0
    <=>\(\left[ \begin{array}{l}x=0\\x^2-4=0\end{array} \right.\) 
    <=>\(\left[ \begin{array}{l}x=0\\x=-2\\x=2\end{array} \right.\) 
    \text( Bảng biến thiên:)
    \begin{array}{|c|cc|}\hline \text{$x$}&\text{$-\infty$}&\text{}&\text{-2}&\text{}&\text{-1}&\text{}&\text{0}&\text{}&\text{}&\text{2}&\text{}&\text{3}&\text{}&\text{$+\infty$}\\\hline \text{$f'(x)$}&\text{}&\text{//}&\text{//}&\text{//}&\text{|}&\text{$-$}&\text{0}&\text{}&\text{+}&\text{0}&\text{$-$}&\text{|}&\text{//}&\text{//}\\\hline \text{$f(x)$}&\text{}&\text{}&\text{}&\text{}&\text{m+7}&\text{}&\text{}&\text{}&\text{}&\text{m+16}\\&\text{}&\text{//}&\text{//}&\text{//}&\text{|}&\text{$\searrow$}&\text{}&\text{}&\text{$\nearrow$}&\text{}&\text{$\searrow$}&\text{|}&\text{//}&\text{//}\\&\text{}&\text{}&\text{}&\text{}&\text{}&\text{}&\text{m}&\text{}&\text{}&\text{}&\text{}&\text{ m-9}\\\hline \end{array}
    ->max_{[-1;3]}f(x)=f(2)=m+16;min_{[-1;3]}f(x)=f(3)=m-9
    *TH1: m-9>0<=>m>9
    ->min_{[-1;3]}y=m-9
    ->m-9=2018
    ->m=2027(tmđk)
    *TH2: m+16<0<=>m<-16
    ->min_{[-1;3]}y=-(m+16)
    ->-(m+16)=2018
    ->-m-16=2018
    ->m=-2034(tmđk)
    text( Vậy)m∈{-2034;2027}

  2. Giải đáp và giải thích các bước giải:
    Ảnh 

    toan-lop-12-tim-m-de-y-4-8-2-m-thuoc-1-3-bang-co-min-bang-2018

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222-9+11+12:2*14+14 = ? ( )