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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 5: A=4/1×5+4/5×9+4/9×3+…+4/97×101 Làm nhanh với ạ!

Toán Lớp 5: A=4/1×5+4/5×9+4/9×3+…+4/97×101
Làm nhanh với ạ!

Comments ( 2 )

  1. Giải đáp:
    $A=\dfrac{100}{101}$.
    Lời giải và giải thích chi tiết:
    $A=\dfrac4{1\times5}+\dfrac4{5\times9}+\dfrac4{9\times13}\ +\,.\!.\!.+\ \dfrac4{97\times101}\\A=\dfrac{5-1}{1\times5}+\dfrac{9-5}{5\times9}+\dfrac{13-9}{9\times13}\ +\,.\!.\!.+\ \dfrac{101-97}{97\times101}\\A=\dfrac5{1\times5}-\dfrac1{1\times5}+\dfrac9{5\times9}-\dfrac5{5\times9}+\dfrac{13}{9\times13}-\dfrac9{9\times13}\ +\,.\!.\!.+\ \dfrac{101}{97\times101}-\dfrac{97}{97\times101}\\A=1-\dfrac15+\dfrac15-\dfrac19+\dfrac19-\dfrac1{13}\ +\,.\!.\!.+\ \dfrac1{97}-\dfrac1{101}\\A=1-\dfrac1{101}\\A=\dfrac{100}{101}$

  2. Bạn sai đề nha 
    Sửa đề : A=4/1×5+4/5×9+4/9 x 13+…+4/97×101
    ________________________________________________
    A = $\dfrac{4}{1 × 5}$ +  $\dfrac{4}{5 × 9}$ + $\dfrac{4}{9 × 13}$ + … + $\dfrac{4}{97 × 101}$
    A= $\dfrac{5 – 1}{1 × 5}$ +  $\dfrac{9 – 5}{5 × 9}$ + $\dfrac{13 – 9}{9 × 13}$ + … +
    $\dfrac{101 – 97}{97 × 101}$
    A= 1 – $\dfrac{1}{5}$ + $\dfrac{1}{5}$ – $\dfrac{1}{9}$ + … + $\dfrac{1}{97}$ –
    $\dfrac{1}{101}$
    A = 1 – $\dfrac{1}{101}$
    A= $\dfrac{100}{101}$
     

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222-9+11+12:2*14+14 = ? ( )