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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: 1) Sinx + Sin2x + Sin3x =0 2) Sinx + Sin2x + Sin3x + Sin4x =0 3) Sin ²x + sin ² 3x = Cos ² 2x + Cos ² 4x mn ơi giúp em với em cảm ơn

Toán Lớp 11: 1) Sinx + Sin2x + Sin3x =0
2) Sinx + Sin2x + Sin3x + Sin4x =0
3) Sin ²x + sin ² 3x = Cos ² 2x + Cos ² 4x
mn ơi giúp em với
em cảm ơn

Comments ( 2 )

  1. 1. 
    $\sin x+\sin3x+\sin2x=0$
    $\to 2\sin2x.\cos x+\sin2x=0$
    $\to \sin2x(2\cos x+1)=0$
    $\to \left[ \begin{array}{l}
    \sin2x=0\\  
    \cos x=\dfrac{-1}{2}\end{array} \right.$
    $\to \left[ \begin{array}{l}x=\dfrac{k\pi}{2}\\
    x=\pm\dfrac{2\pi}{3}+k2\pi\end{array} \right.$
    2.
    $\sin x+\sin4x+\sin2x+\sin3x=0$
    $\to 2\sin\dfrac{5x}{2}\cos\dfrac{3x}{2}+2\sin\dfrac{5x}{2}\sin\dfrac{x}{2}=0$
    $\to 2\sin\dfrac{5x}{2}\left( \cos\dfrac{3x}{2}+\cos\dfrac{x}{2}\right)=0$
    $\to 2\sin\dfrac{5x}{2}.2\cos x.\cos\dfrac{x}{2}=0$
    $\to \left[\begin{array}{l} \sin x=\dfrac{5x}{2}\\
    \cos x=0\\
    \cos\dfrac{x}{2}=0\end{array}\right.$
    $\to \left[\begin{array}{l} x=\dfrac{k2\pi}{5}\\
    x=\dfrac{\pi}{2}+k\pi\\
    x=\pi+k2\pi \end{array}\right.$
    3.
    $\sin^2x+\sin^23x=\cos^22x+\cos^24x$
    $\to \dfrac{1-\cos2x+1-\cos6x}{2}=\dfrac{1+\cos4x+1+\cos8x}{2}$
    $\to \cos2x+\cos8x+\cos4x+\cos6x=0$
    $\to 2\cos5x.\cos3x+2\cos5x.\cos x=0$
    $\to 2\cos5x(\cos3x+\cos x)=0$
    $\to 2\cos5x.2\cos2x.\cos x=0$
    $\to \left[\begin{array}{l} \cos5x=0 \\
    \cos2x=0 \\
    \cos x=0\\ 
    \end{array}\right.$
    $\to \left[\begin{array}{I}
    x=\dfrac{\pi}{10}+\dfrac{k\pi}{5}\\
    x=\dfrac{\pi}{4}+\dfrac{k\pi}{2}\\
    x=\dfrac{\pi}{2}+k\pi
    \end{array}\right.$

  2. Đáp án:
     
    Giải thích các bước giải:
     

    toan-lop-11-1-sin-sin2-sin3-0-2-sin-sin2-sin3-sin4-0-3-sin-sin-3-cos-2-cos-4-mn-oi-giup-em-voi-e

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222-9+11+12:2*14+14 = ? ( )