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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Tìm min Y = √(x ²/4 -x/6+1)

Toán Lớp 9: Tìm min
Y = √(x ²/4 -x/6+1)

Comments ( 2 )

  1. Giải đáp:
    $MinY=\dfrac{\sqrt{35}}{6}$ <=>x=1/3 
    Lời giải và giải thích chi tiết:
    $Y=\sqrt{\dfrac{x^2}{4}-\dfrac{x}{6}+1}$
    $=\sqrt{\bigg(\dfrac{x^2}{4}-2.\dfrac{x}{2}.\dfrac{1}{6}+\dfrac{1}{36}\bigg)+\dfrac{35}{36}}$
    $=\sqrt{\bigg(\dfrac{x}{2}+\dfrac{1}{6}\bigg)^2+\dfrac{35}{36}}\ge\dfrac{\sqrt{35}}{6}$
    Dấu “=” xảy ra <=>x=1/3
    Vậy $MinY=\dfrac{\sqrt{35}}{6}$ <=>x=1/3

  2. Y=sqrt{x^2/4-x/6+1}
    Y=sqrt{(x/2)^2-2. x/2. 1/6+1/36+35/36}
    Y=sqrt{(x/2-1/6)^2+35/36}>=sqrt{35/36}=sqrt{35}/6
    Dấu = xảy ra khi x/2=1/6
                            <=> x=1/3
    Vậy Y_(min)=sqrt{35}/6<=>x=1/3
     

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222-9+11+12:2*14+14 = ? ( )