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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn biểu thức sau : a) (x – 3)³ – (x – 3)(x² + 3x + 9) +6(x + 1)² b) (x² – 1)³ – (x^4 + x² + 1)(x² – 1) c) (x^4 – 3x² +

Toán Lớp 8: Rút gọn biểu thức sau :
a) (x – 3)³ – (x – 3)(x² + 3x + 9) +6(x + 1)²
b) (x² – 1)³ – (x^4 + x² + 1)(x² – 1)
c) (x^4 – 3x² + 9)(x² + 3) – (3 + x²)³

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
     a) (x-3)³ – (x-3)(x² + 3x +9) + 6(x+1)²
    = x³ – 9x² + 27x – 27 – (x³ – 27) + 6(x² + 2x + 1)
    = x³ – 9x² + 27x – 27 – x³ + 27 + 6x² + 12x + 6
    = -3x² + 39x + 6
    b) (x²-1)³ – (x^4 + x² + 1)(x²-1)
    = (x² – 1)[(x²-1)² – (x^4+x²+1)]
    = (x²-1)(x^4 – 2x² + 1 – x^4 – x² – 1)
    =  -3x².(x²-1)
    = -3x^4 + 3x²
    c) (x^4 – 3x² + 9)(x²+3) – (3+x²)³
    = (x²+3)[(x^4-3x²+9) – (x²+3)²]
    = (x²+3)(x^4 – 3x² + 9 – x^4 – 6x² – 9)
    = -9x².(x²+3)
    = -9x^4 – 27x²

  2. a)
    (x-3)^3 – (x-3)(x^2 + 3x+9) + 6 (x+1)^2
    =  (x^3 – 3 . x^2 . 3 + 3 . x . 3^2 – 3^3) – (x-3)(x^2 + x . 3 + 3^2) + 6 . (x^2 + 2 . x . 1 + 1^2)
    = (x^3 – 9x^2 + 27x  – 27) – (x^3 – 3^3) + 6 (x^2 + 2x+1)
    =  (x^3 – 9x^2 + 27x -27) – (x^3 – 27) + (6x^2 + 12x+6)
    =  x^3 – 9x^2 + 27x – 27 – x^3 + 27 + 6x^2 + 12x+  6
    = (x^3 – x^3) + (6x^2 – 9x^2) + (27x + 12x) + (6-27 + 27)
    = -3x^2 + 39x +6
    b)
    (x^2 – 1)^3 – (x^4 + x^2 + 1)(x^2 – 1)
    =  [(x^2)^3 – 3 . (x^2)^2 . 1 + 3 . x^2 . 1^2 – 1^3) – [ (x^2)^2 + x^2 . 1 + 1^2] (x^2 -1)
    =  (x^6 – 3x^4 + 3x^2- 1) – [ (x^2)^3 – 1^3]
    =  x^6 – 3x^4 + 3x^2 – 1 – x^6 + 1
    =  (x^6 – x^6) – 3x^4 + 3x^2 + (1-1)
    = -3x^4 + 3x^2
    c)
    (x^4 -3x^2 + 9)(x^2 + 3) – (3 + x^2)^3
    =[ (x^2)^2 – 3 . x^2 + 3^2] (x^2 + 3) – [ 3^3 + 3 . 3^2 . x^2 + 3 . 3 . (x^2)^2 +  (x^2)^3]
    = [ (x^2)^3 + 3^3]- (27 + 27x^2 + 9x^4 + x^6)
    = x^6 + 27 – 27 – 27x – 9x^4 – x^6
    = (x^6 – x^6) – 9x^4 – 27x^2 + (27-27)
    =  -9x^4 – 27x^2
     

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222-9+11+12:2*14+14 = ? ( )