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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm X, biết b) ( 3x +2 ). ( 2x + 9 ) – ( x + 2 ). ( 6x + 1 ) – ( x + 1 ) – ( x – 6 ) c) 3.( 2x – 1). ( 3x – 1 ) – ( 2x – 3 ) , ( 9x –

Toán Lớp 8: Tìm X, biết
b) ( 3x +2 ). ( 2x + 9 ) – ( x + 2 ). ( 6x + 1 ) – ( x + 1 ) – ( x – 6 )
c) 3.( 2x – 1). ( 3x – 1 ) – ( 2x – 3 ) , ( 9x – 1 ) = 0

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
     b) (3x + 2)(2x + 9) – (x + 2)(6x + 1) = (x + 1) – (x – 6)
    ⇔ 6x² + 27x + 4x + 18 – (6x² + x + 12x + 2) = x + 1 – x + 6
    ⇔ 6x² + 31x + 18 – 6x² – 13x – 2 = 7
    ⇔ 18x = -9
    ⇔   x  = \frac{-1}{2}
    c) 3(2x – 1)(3x – 1) – (2x – 3)(9x – 1) = 0
    ⇔ 3(6x² – 2x – 3x + 1) – (18x² – 2x – 27x + 3) = 0
    ⇔ 18x² – 6x – 9x + 3 – 18x² + 2x + 27x – 3 = 0
    ⇔ 14x = 0
    ⇔    x = 0

  2. Giải đáp+Lời giải và giải thích chi tiết:
     b)(3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)
    <=>6x^2+27x+4x+18-6x^2-x-12x-2=x+1-x+6
    <=>(6x^2-6x^2)+(27x+4x-x-12x+x)+(18-2-1-6)=0
    <=>18x+9=0
    <=>x=-1/2
    Vậy x=-1/2
    c)3(2x-1)(3x-1)-(2x-3)(9x-1)=0
    <=>3(6x^2-5x+1)-(18x^2-29x+3)=0
    <=>18x^2-15x+3-18x^2+29x-3=0
    <=>14x=0
    <=>x=0
    Vậy x=0

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222-9+11+12:2*14+14 = ? ( )