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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: $\sqrt[3]{x-9}+2x^2+3x=$$\sqrt[]{5x-1}+1$

Tháng Một 7, 2023 Toán học 1 Comment 0 views

Toán Lớp 9: $\sqrt[3]{x-9}+2x^2+3x=$$\sqrt[]{5x-1}+1$

Comments ( 1 )

  1. dinhcongson
    dinhcongson
    7 Tháng Một, 2023 at 4:23 chiều
    Reply
    Giải đáp:
    \root{3}{x – 9} + 2x^2 + 3x =\sqrt{5x -1} +1 ( ĐK: x≥ 1/5)$\\$ <=> \root{3}{x – 9} + 2x^2 + 3x- \sqrt{5x -1} – 1= 0 $\\$ <=> 2\root{3}{x – 9} + 4x^2 + 6x -2\sqrt{5x -1} -2 = 0$\\$ <=> 2 ( \root{3}{x -9}+2) + ( 5x -1 – 2\sqrt{5x -1}) + 4x^2 + x -5 = 0$\\$ <=> (2(x-1))/((\root{3}{x-9})^2 – 2\root{3}{x-9}+ 4) + (5(x-1)\sqrt{5x-1})/(\sqrt{5x -1} +2) + ( x -1) ( 4x +5) = 0$\\$<=> (x -1)( 2/((\root{3}{x -9} -1)^2 +3) +(5\sqrt{ 5x -1})/(\sqrt{5x -1} +2) + 4x + 5) = 0$\\$ <=> x = 1

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222-9+11+12:2*14+14 = ? ( )

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