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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Rút gọn : √ 6 + 2 √5 – √6 – 2√5 √11+ 6 √2 – √ 11 – 6√2

Toán Lớp 9: Rút gọn :
√ 6 + 2 √5 – √6 – 2√5
√11+ 6 √2 – √ 11 – 6√2

Comments ( 2 )

  1. Mình không biết đề như nào :

    ______________________________________

    a)

    sqrt6+2sqrt5-sqrt6-2sqrt5

    =sqrt6 -sqrt6 +2sqrt5 -sqrt5

    =0

    b) sqrt11+6sqrt2 -sqrt11-6sqrt2

    =sqrt11-sqrt11+6sqrt2-6sqrt2

    =0

    ____________________________________________

    a)

    sqrt{6+2sqrt5}-{sqrt6-2sqrt5}

    =sqrt{5+2sqrt5+1}-sqrt{5-2sqrt5+1}

    =sqrt{(sqrt5)^2+2*sqrt5*1+1^2}-sqrt{(sqrt5)^2-2*sqrt5*1+1^2}

    =sqrt{(sqrt5+1)^2}-sqrt{(sqrt5-1)^2}

    =|sqrt5+1|-|sqrt5-1|

    =sqrt5+1-sqrt5+1 (Vì sqrt5+1>0 ; sqrt5-1>0 )

    =2

    b)

    sqrt{11+6sqrt2}-sqrt{11-6sqrt2}

    =sqrt{9+6sqrt2+2}-sqrt{9-6sqrt2+2}

    =sqrt{3^2+2*3*sqrt2+(sqrt2)^2}-sqrt{3^2-2*3*sqrt2+(sqrt2)^2}

    =sqrt{(3+sqrt2)^2}-sqrt{(3-sqrt2)^2}

    =|3+sqrt2|-|3-sqrt2|

    =3+sqrt2-3+sqrt2 (Vì 3+sqrt2>0 ; 3-sqrt2>0 )

    =2sqrt2

  2. Giải thích các bước :
    \sqrt{6 + 2\sqrt{5}} – \sqrt{6 – 2\sqrt{5}}
    = \sqrt{5 + 2\sqrt{5} + 1} – \sqrt{5 – 2\sqrt{5} + 1}
    = \sqrt{(\sqrt{5} + 1)^2} – \sqrt{(\sqrt{5} – 1)^2}
    = |\sqrt{5} + 1| – |\sqrt{5} – 1|
    = \sqrt{5} + 1 – \sqrt{5} + 1
    = 2
    \sqrt{11 + 6\sqrt{2}} – \sqrt{11 – 6\sqrt{2}}
    = \sqrt{9 + 6\sqrt{2} + 2} – \sqrt{9 – 6\sqrt{2} + 2}
    = \sqrt{(3 + \sqrt{2})^2} – \sqrt{(3 – \sqrt{2})^2}
    = |3 + \sqrt{2}| – |3 – \sqrt{2}|
    = 3 + \sqrt{2} – 3 + \sqrt{2}
    = 2\sqrt{2}

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222-9+11+12:2*14+14 = ? ( )