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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Giải hệ phương trình x+1=2(y-1)=2(y-1) x-1= y+1

Toán Lớp 9: Giải hệ phương trình x+1=2(y-1)=2(y-1)
x-1= y+1

Comments ( 2 )

  1. $\begin{cases}x+1=2(y-1)\\x-1=y+1\end{cases}$
    Ta có : x-1=y+1
    =>x-1+1=y+1+1
    =>x+(1-1)=y+(1+1)
    =>x+0=y+2
    =>x=y+2
    ________________
    x+1=2(y-1)
    =>x+1=2.y-2.1
    =>x+1=2.y-2
    Thay x=y+2 được :
    =>y+2+1=2y-2
    =>y+3=2y-2
    =>2+3=2y-y
    =>5=y
    =>x=y+2
    =>x=5+2=7
    Vậy (x;y)=(7;5)

  2. {(x+1=2(y-1)),(x-1 = y+1):} \Leftrightarrow {(x+1=2y-2),(x-1 = y+1):} \Leftrightarrow {(2y-2-y-1 = 2),(x-1 = y+1):} $\\$ \Leftrightarrow {(y-3 = 2),(x-1 = y+1):} \Leftrightarrow {(y=5),(x-1 = 5+1):} \Leftrightarrow {(y=5),(x=7):}
    Chúc ban học tốt.
     

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222-9+11+12:2*14+14 = ? ( )

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