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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: ( $\frac{1}{1- \sqrt[]{a}}$ – $\frac{1}{1+\sqrt[]{a}}$ ).$\frac{\sqrt[]{a}-1}{\sqrt[]{a}}$ với a > 0 và a $ \neq$ 1

Toán Lớp 9: ( $\frac{1}{1- \sqrt[]{a}}$ – $\frac{1}{1+\sqrt[]{a}}$ ).$\frac{\sqrt[]{a}-1}{\sqrt[]{a}}$ với a > 0 và a $ \neq$ 1

Comments ( 2 )

  1. (1/(1-\sqrt[a])-1/(1+\sqrt[a])). (\sqrt[a]-1)/(\sqrt[a])(a>0;ane1)
    =(1+\sqrt[a]-1+\sqrt[a])/((1-\sqrt[a])(1+\sqrt[a])). (1-\sqrt[a])/(-\sqrt[a])
    =(2\sqrt[a])/((1-\sqrt[a])(1+\sqrt[a])). (1-\sqrt[a])/(-\sqrt[a])
    =-(2)/(1+\sqrt[a])

  2. ((1)/(1-\sqrt{a})-1/(1+\sqrt{a})).(\sqrt{a}-1)/(\sqrt{a}) (a>0,ane1)
    =[(1+\sqrt{a}-1+\sqrt{a})/((1-\sqrt{a})(1+\sqrt{a}))].(\sqrt{a}-1)/(\sqrt{a})
    =(2\sqrt{a})/((1-\sqrt{a})(1+\sqrt{a})).(-(1-\sqrt{a}))/(\sqrt{a})
    =(-2\sqrt{a}(1-\sqrt{a}))/(\sqrt{a}(1-\sqrt{a})(1+\sqrt{a}))
    =(-2)/(1+\sqrt{a})
     

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222-9+11+12:2*14+14 = ? ( )

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