Toán Lớp 9: cứu e với !!
2$\sqrt{2x + 1}$ – $\dfrac{3}{4}$$\sqrt{8x + 4}$ = $\sqrt{\dfrac{18x + 9}{4} – 3}$
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Toán Lớp 9: cứu e với !!
2$\sqrt{2x + 1}$ – $\dfrac{3}{4}$$\sqrt{8x + 4}$ = $\sqrt{\dfrac{18x + 9}{4} – 3}$
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