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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: cho tam giác ABC có AB=c,AC=b,BC=a . CMR: a/(b+c-a)+b/(a+c-b)+c/(a+b-c) ≥3

Toán Lớp 9: cho tam giác ABC có AB=c,AC=b,BC=a .
CMR: a/(b+c-a)+b/(a+c-b)+c/(a+b-c) ≥3

Comments ( 2 )

  1. Đặt $b+c-a=x$, $a+c-b=y$, $a+b-c=z$
    $\Rightarrow b+c-a+a+c-b=x+y\Rightarrow 2c=x+y\Rightarrow c=\dfrac{x+y} 2$
    Tương tự $a=\dfrac{y+z} 2, b=\dfrac{x+z} 2$
    Do đó:
    $\begin{array}{l}
    \dfrac{a}{{b + c – a}} + \dfrac{b}{{a + c – b}} + \dfrac{c}{{a + b – c}} = \dfrac{{y + z}}{{2x}} + \dfrac{{x + z}}{{2y}} + \dfrac{{x + y}}{{2z}}\\
     = \dfrac{1}{2}\left( {\dfrac{x}{y} + \dfrac{y}{x} + \dfrac{y}{z} + \dfrac{z}{y} + \dfrac{z}{x} + \dfrac{x}{z}} \right) \ge \dfrac{1}{2}\left( {2 + 2 + 2} \right) = 3\\
     \Rightarrow \dfrac{a}{{b + c – a}} + \dfrac{b}{{a + c – b}} + \dfrac{c}{{a + b – c}} \ge 3\\
    ‘ = ‘ \Leftrightarrow x = y = z \Leftrightarrow a = b = c
    \end{array}$
     

  2. Đáp án:
     
    Giải thích các bước giải:
     

    toan-lop-9-cho-tam-giac-abc-co-ab-c-ac-b-bc-a-cmr-a-b-c-a-b-a-c-b-c-a-b-c-3

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222-9+11+12:2*14+14 = ? ( )