Toán Lớp 9: Cho A=(1/x+2 √x – 1/ √x+2): 1- √x/ x+4 √x +4 với x>0, x khác 0
a rút gọn A
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Toán Lớp 9: Cho A=(1/x+2 √x – 1/ √x+2): 1- √x/ x+4 √x +4 với x>0, x khác 0
a rút gọn A
Comments ( 1 )
A = \left( {\dfrac{1}{{x + 2\sqrt x }} – \dfrac{1}{{\sqrt x + 2}}} \right):\dfrac{{1 – \sqrt x }}{{x + 4\sqrt x + 4}}\\
= \dfrac{{1 – \sqrt x }}{{\sqrt x \left( {\sqrt x + 2} \right)}}.\dfrac{{{{\left( {\sqrt x + 2} \right)}^2}}}{{1 – \sqrt x }}\\
= \dfrac{{\sqrt x + 2}}{{\sqrt x }}
\end{array}\)